(1+3+5+........+2011) x (125125 x 127-127127 x 125)

=(1+3+5+............+2011) x (125 x 1001 x 127-127 x 1001 x 125)

=(1+3+5+..........+2011) x 0

=0

Câu 2:Tính tổng: 1+3+5+7+......+2007

Khoảng cách của từng số hạng là 2

    Số số hạng của dãy là:

        (2007-1):2+1=1004(số hạng)

Câu 1:Tính nhanh:(1+3+5+....+2011)x(125125x127-127127x125)

Ta có:

=(125125x127-127127x125)

=1001x125x127-1001x127x125

=0

Vậy:(1+3+5+....+2011)x(125125x127-127127x125)=(1+3+5+....+2011)x0=0

[ 1 + 3 + 5 + 7 + ... + 2011 + 2013 ] x [ 125125 x 127 - 127127 x 125 ]

= [ ( 2013 + 1 ) x 1007 : 2 ] x [ ( 125 x 1001 )  x 127 - ( 127 x 1001 ) x 125 ]

= 1008007 x [ 125 x 1001 x 127 - 127 x 1001 x 125 ]

= 1008007 x [ ( 125 - 125 ) x ( 127 - 127 ) x ( 1001 - 1001 ) ]

= 1008007 x [ 0 x 0 x 0 ]

= 1008007 x 0

= 0

= minh chiu ban tu lam

Ta có : ( 1+3+5+7+...+2011+2013 ) x ( 125125x127-127127x125 )

=         ( 1+3+5+7+...+2011+2013 ) x ( 125x1001x127-127x1001x125 )

=         ( 1+3+5+7+...+2011+2013 ) x 0

=         0

Tk và kb vs mk nak ^_^

1 ) 

= (1 + 3+ 5+ .....+2003+2005) \(\times\)( 125 nhân 1001 NHÂN 127 - 127 nhân 1001 nhân 125 )

= (1 + 3+ 5+ .....+2003+2005) \(\times\)0

= 0

Chúc bạn học tốt

Trả lời:

Bài 1 

\(\left(1+3+5+...+2003+2005\right)\times\left(125125\times127-127127\times125\right)\)

\(=\left\{\left(2005+1\right)\times\left[\left(2005-1\right)\div2+1\right]\div2\right\}\times\left(125\times1001\times127-127\times1001\times125\right)\)

\(=\left(2006\times1003\div2\right)\times0\)

\(=10061009\times0\)

\(=0\)

Bài 2 

\(y-6\div2-\left(48-24\times2\div6-3\right)=0\)

\(y-3-\left(48-8-3\right)=0\)

\(y-3-37=0\)

\(y-40=0\)

\(y=40\)

Vậy \(y=40\)

2) 

y - 3 - ( 48 - 48 : 6 - 3 ) = 0

y - 3 - ( 48 - 8 - 3 ) = 0

y - 3 - 32 = 0

y - 3 = 0 + 32

y - 3 = 32

y = 32+3

y = 35

Chúc bạn học tốt nhoa ! ~

\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)

\(=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+...+\frac{1}{13\cdot15}\)

\(=\frac{1}{2}\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{13\cdot15}\right)\)

\(=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\right)\)

\(=\frac{1}{2}\left(1-\frac{1}{15}\right)\)

\(=\frac{1}{2}\cdot\frac{14}{15}\)

\(=\frac{7}{15}\)

Sửa đề chút nhé:

\(\left(1+3+5+7+...+2009+2011\right).\left(125125.127-127127.125\right)\)

\(=\left(1+3+5+7+...+2009+2011\right).\left(125.1001.127-127.1001.125\right)\)

\(=\left(1+3+5+7+...+2009+2011\right).0\)

\(=0\)

Ý b tham khảo bài bạn nguyen thi thuy linh nhé

\(\text{Tính nhanh : }\)

\(a,\text{ }1+3+5+7+9+\text{...}+2007+2009+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)

\(=\left\{\left(2009-1\right)\text{ : }2+1\right\}\cdot\left(2009+1\right)\text{ : }2+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)

\(=1005\cdot2010\text{ : }2+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)

\(=2020050\text{ : }2+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)

\(=1010025+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)

\(=1010025+2011\cdot\left(15890875+15890875\right)\)

\(=1010025+2011\cdot15890875\cdot2\)

\(=1010025+31956549625\cdot2\)

\(=1010025+63913099250\)

\(=63914109275\)

\(b,\text{ }\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)

\(=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}+\frac{1}{13\cdot15}\)

\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{13}-\frac{1}{15}\)

\(=1-\frac{1}{15}\)

\(=\frac{14}{15}\)

Vì 125 125x127 – 127 127x125 = 1001x125x127 – 1001x127x125 = 0                     

     nên : (1+3+5+...+2005)(125 125x127 – 127 127x125) = 0

( 1+3+5+7+…+2003+2005) x (125 125 x 127 – 127 127 x 125)

= ( 1+3+5+7+…+2003+2005) x (125 x 1001 x 127 – 127 x 1001x 125)

=  ( 1+3+5+7+…+2003+2005) x                   0  =    0

a. Vì 125 125x127 – 127 127x125 = 1001x125x127 – 1001x127x125 = 0                     

nên : (1+3+5+...+2005)(125 125x127 – 127 127x125) = 0

b. 

19 , 8 : 0 , 2 x 44 , 44 x 2 x 13 , 2 : 0 , 25 3 , 3 x 88 , 88 : 0 , 5 x 6 , 6 : 0 , 125 x 5 = 19 , 8 x 5 x 88 , 88 x 13 , 2 x 4 3 , 3 x 88 , 88 x 2 x 6 , 6 x 8 x 5 = 19 , 8 x 5 x 88 , 88 x 13 , 2 x 4 3 , 3 x 88 , 88 x 13 , 2 x 4 x 2 x 5 = 19 , 8 3 , 3 x 2 = 3

Dài thế